# What is the magnitude of the electric field at the midpoint of any of the three sides of the triangle?

A point charge q = 5.0 µC is placed at each corner of an equilateral triangle with sides 0.20m in length.

A) What is the magnitude of the electric field at the midpoint of any of the three sides of the triangle?

B) Is the magnitude of the electric field at the center of the triangle greater than, less than, or the same as the magnitude at the midpoint of a side? Explain.

please help me please.

A) What is the magnitude of the electric field at the midpoint of any of the three sides of the triangle?

B) Is the magnitude of the electric field at the center of the triangle greater than, less than, or the same as the magnitude at the midpoint of a side? Explain.

please help me please.

Answer:

I have arranged the charges as above at the three vertices of equilateral triangle.

so according to the diagram, at any side of the triangle, fields of two charges will neutralize each other. So, only the field due to one remaining charge will be the net electric field.

In the above diagram, the red vector and the black vector neutralizes each other. So, only the violet vector remains.

So, the net electric field will be due to one charge only.

But, at the centre, all the field vectors from the individual charges will act. According to the diagram, they make an angle of 120 deg with each other. So, the net force becomes zero.

## No comments:

## Post a Comment